Two monochromatic sources of electromagnetic wave, P and Q emit waves of wavelength λ = 20 m and separated by 5m as shown. A, B and C are three points where interference of these waves is observed. If phase of a wave generated by P is ahead of wave generated by Q by π/2 then (given intensity of both waves is I):
Text Solution
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(a, b, d)
Wave emitted from Q y =A sin ( ω t –kx Q )
Wave emitted from P y = A sin ( ω t –kx p + 
)
Δφ = φ p – φ Q = ω t – kx p + 
– ( ω t – kx Q )
= k (x Q – x p ) + 
= 
(x Q – x p ) + 
= 
(x Q – x p ) + 
For A , x Q – x P = – 5
⇒ Δφ = 
(– 5) + 
= 0
For B x Q – x P = 5
⇒ Δφ = π
For C x Q – x P = 0
⇒ Δφ = 
Ι Α : Ι Β : Ι C = ( Ι + Ι + 2 Ι cos0) : ( Ι + Ι + 2 Ι cos π ) : ( Ι + Ι + 2 Ι cos 
)
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